Base | Representation |
---|---|
bin | 111101001111100110… |
… | …1111100101000110011 |
3 | 110120110212120001221202 |
4 | 1322133031330220303 |
5 | 4123323141034332 |
6 | 140230343241415 |
7 | 12334123462202 |
oct | 1723715745063 |
9 | 416425501852 |
10 | 131520252467 |
11 | 5086083232a |
12 | 215a5a4926b |
13 | c52cb380c6 |
14 | 6519361239 |
15 | 364b55da62 |
hex | 1e9f37ca33 |
131520252467 has 2 divisors, whose sum is σ = 131520252468. Its totient is φ = 131520252466.
The previous prime is 131520252401. The next prime is 131520252511. The reversal of 131520252467 is 764252025131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131520252467 - 224 = 131503475251 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131520252467.
It is not a weakly prime, because it can be changed into another prime (131520252167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65760126233 + 65760126234.
It is an arithmetic number, because the mean of its divisors is an integer number (65760126234).
Almost surely, 2131520252467 is an apocalyptic number.
131520252467 is a deficient number, since it is larger than the sum of its proper divisors (1).
131520252467 is an equidigital number, since it uses as much as digits as its factorization.
131520252467 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 100800, while the sum is 38.
Adding to 131520252467 its reverse (764252025131), we get a palindrome (895772277598).
The spelling of 131520252467 in words is "one hundred thirty-one billion, five hundred twenty million, two hundred fifty-two thousand, four hundred sixty-seven".
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