131521034121403 has 4 divisors (see below), whose sum is σ = 131521435468480. Its totient is φ = 131520632774328.

The previous prime is 131521034121359. The next prime is 131521034121511. The reversal of 131521034121403 is 304121430125131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131521034121403 is a prime.

It is a super-2 number, since 2×131521034121403² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131521034128403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200181588 + ... + 200837521.

It is an arithmetic number, because the mean of its divisors is an integer number (32880358867120).

Almost surely, 2^{131521034121403} is an apocalyptic number.

131521034121403 is a deficient number, since it is larger than the sum of its proper divisors (401347077).

131521034121403 is an equidigital number, since it uses as much as digits as its factorization.

131521034121403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 401347076.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 131521034121403 its reverse (304121430125131), we get a palindrome (435642464246534).

The spelling of 131521034121403 in words is "one hundred thirty-one trillion, five hundred twenty-one billion, thirty-four million, one hundred twenty-one thousand, four hundred three".