Search a number
-
+
131521202321557 is a prime number
BaseRepresentation
bin11101111001111000101010…
…100010110111100010010101
3122020200022012201112221212011
4131321320222202313202111
5114214320410243242212
61143420001203024221
736463044000121546
oct3571705242674225
9566608181487764
10131521202321557
11389a7912a61614
121290183466b071
13585051c4a1499
1424699356864cd
15103127d0074a7
hex779e2a8b7895

131521202321557 has 2 divisors, whose sum is σ = 131521202321558. Its totient is φ = 131521202321556.

The previous prime is 131521202321533. The next prime is 131521202321563. The reversal of 131521202321557 is 755123202125131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112129165879236 + 19392036442321 = 10589106^2 + 4403639^2 .

It is a cyclic number.

It is not a de Polignac number, because 131521202321557 - 227 = 131521068103829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131521202321507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65760601160778 + 65760601160779.

It is an arithmetic number, because the mean of its divisors is an integer number (65760601160779).

Almost surely, 2131521202321557 is an apocalyptic number.

It is an amenable number.

131521202321557 is a deficient number, since it is larger than the sum of its proper divisors (1).

131521202321557 is an equidigital number, since it uses as much as digits as its factorization.

131521202321557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126000, while the sum is 40.

Adding to 131521202321557 its reverse (755123202125131), we get a palindrome (886644404446688).

The spelling of 131521202321557 in words is "one hundred thirty-one trillion, five hundred twenty-one billion, two hundred two million, three hundred twenty-one thousand, five hundred fifty-seven".