Search a number
-
+
13152142023 = 34793277603
BaseRepresentation
bin11000011111110110…
…11100001011000111
31020221121002001002020
430033323130023013
5203413422021043
610013024014223
7643631235246
oct141773341307
936847061066
1013152142023
11563a04aa69
122670761373
131317a70877
148caa5095d
1551e9a5e83
hex30fedc2c7

13152142023 has 8 divisors (see below), whose sum is σ = 17909299968. Its totient is φ = 8581539384.

The previous prime is 13152142013. The next prime is 13152142033. The reversal of 13152142023 is 32024125131.

It is an interprime number because it is at equal distance from previous prime (13152142013) and next prime (13152142033).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13152142023 - 218 = 13151879879 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13152141984 and 13152142002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13152142013) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46638661 + ... + 46638942.

It is an arithmetic number, because the mean of its divisors is an integer number (2238662496).

Almost surely, 213152142023 is an apocalyptic number.

13152142023 is a deficient number, since it is larger than the sum of its proper divisors (4757157945).

13152142023 is an equidigital number, since it uses as much as digits as its factorization.

13152142023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93277653.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 13152142023 its reverse (32024125131), we get a palindrome (45176267154).

The spelling of 13152142023 in words is "thirteen billion, one hundred fifty-two million, one hundred forty-two thousand, twenty-three".

Divisors: 1 3 47 141 93277603 279832809 4384047341 13152142023