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131521433 is a prime number
BaseRepresentation
bin1111101011011…
…01101110011001
3100011110222111012
413311231232121
5232132141213
621014543305
73154625261
oct765555631
9304428435
10131521433
1168270aaa
1238067b35
132132c144
14136787a1
15b82e4a8
hex7d6db99

131521433 has 2 divisors, whose sum is σ = 131521434. Its totient is φ = 131521432.

The previous prime is 131521393. The next prime is 131521451. The reversal of 131521433 is 334125131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110103049 + 21418384 = 10493^2 + 4628^2 .

It is a cyclic number.

It is not a de Polignac number, because 131521433 - 216 = 131455897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131521399 and 131521408.

It is not a weakly prime, because it can be changed into another prime (131521483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65760716 + 65760717.

It is an arithmetic number, because the mean of its divisors is an integer number (65760717).

Almost surely, 2131521433 is an apocalyptic number.

It is an amenable number.

131521433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131521433 is an equidigital number, since it uses as much as digits as its factorization.

131521433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1080, while the sum is 23.

The square root of 131521433 is about 11468.2794263133. The cubic root of 131521433 is about 508.5482654540.

Adding to 131521433 its reverse (334125131), we get a palindrome (465646564).

The spelling of 131521433 in words is "one hundred thirty-one million, five hundred twenty-one thousand, four hundred thirty-three".