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13152244155411 = 34384081385137
BaseRepresentation
bin1011111101100011111011…
…0101110100010000010011
31201120100020111201221122010
42333120332311310100103
53210441244000433121
643550020233114003
72525134604514654
oct277307665642023
951510214657563
1013152244155411
114210920a47039
121584babb58903
1374533615928a
1433680186952b
1517c1c02a6376
hexbf63ed74413

13152244155411 has 4 divisors (see below), whose sum is σ = 17536325540552. Its totient is φ = 8768162770272.

The previous prime is 13152244155397. The next prime is 13152244155443. The reversal of 13152244155411 is 11455144225131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13152244155411 - 225 = 13152210600979 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13152244155411.

It is not an unprimeable number, because it can be changed into a prime (13152244155451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2192040692566 + ... + 2192040692571.

It is an arithmetic number, because the mean of its divisors is an integer number (4384081385138).

Almost surely, 213152244155411 is an apocalyptic number.

13152244155411 is a deficient number, since it is larger than the sum of its proper divisors (4384081385141).

13152244155411 is an equidigital number, since it uses as much as digits as its factorization.

13152244155411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4384081385140.

The product of its digits is 96000, while the sum is 39.

The spelling of 13152244155411 in words is "thirteen trillion, one hundred fifty-two billion, two hundred forty-four million, one hundred fifty-five thousand, four hundred eleven".

Divisors: 1 3 4384081385137 13152244155411