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13153000217 = 71879000031
BaseRepresentation
bin11000011111111101…
…01101101100011001
31020221122200122022012
430033332231230121
5203414132001332
610013054235305
7643641441260
oct141776555431
936848618265
1013153000217
11563a586815
122670ab5b35
131317cb1386
148cabd55d7
1551eac53b2
hex30ffadb19

13153000217 has 4 divisors (see below), whose sum is σ = 15032000256. Its totient is φ = 11274000180.

The previous prime is 13153000183. The next prime is 13153000297. The reversal of 13153000217 is 71200035131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13153000217 - 26 = 13153000153 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13153000192 and 13153000201.

It is not an unprimeable number, because it can be changed into a prime (13153000297) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 939500009 + ... + 939500022.

It is an arithmetic number, because the mean of its divisors is an integer number (3758000064).

Almost surely, 213153000217 is an apocalyptic number.

It is an amenable number.

13153000217 is a deficient number, since it is larger than the sum of its proper divisors (1879000039).

13153000217 is an equidigital number, since it uses as much as digits as its factorization.

13153000217 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1879000038.

The product of its (nonzero) digits is 630, while the sum is 23.

Adding to 13153000217 its reverse (71200035131), we get a palindrome (84353035348).

The spelling of 13153000217 in words is "thirteen billion, one hundred fifty-three million, two hundred seventeen", and thus it is an aban number.

Divisors: 1 7 1879000031 13153000217