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1315302055433 = 22034931121081
BaseRepresentation
bin10011001000111110000…
…111001001111000001001
311122202000122212102001222
4103020332013021320021
5133022214311233213
62444124051451425
7164012261001032
oct23107607117011
94582018772058
101315302055433
114678a87a19a3
12192ab7bb6b75
13970563b0a02
1447937959a89
1524332502808
hex1323e1c9e09

1315302055433 has 8 divisors (see below), whose sum is σ = 1316176838496. Its totient is φ = 1314427528800.

The previous prime is 1315302055393. The next prime is 1315302055579. The reversal of 1315302055433 is 3345502035131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1315302055433 - 212 = 1315302051337 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1315302055393 and 1315302055402.

It is not an unprimeable number, because it can be changed into a prime (1315302052433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10802453 + ... + 10923533.

It is an arithmetic number, because the mean of its divisors is an integer number (164522104812).

Almost surely, 21315302055433 is an apocalyptic number.

It is an amenable number.

1315302055433 is a deficient number, since it is larger than the sum of its proper divisors (874783063).

1315302055433 is a wasteful number, since it uses less digits than its factorization.

1315302055433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 128215.

The product of its (nonzero) digits is 81000, while the sum is 35.

The spelling of 1315302055433 in words is "one trillion, three hundred fifteen billion, three hundred two million, fifty-five thousand, four hundred thirty-three".

Divisors: 1 2203 4931 121081 10862993 266741443 597050411 1315302055433