Base | Representation |
---|---|
bin | 1011111101100111001000… |
… | …0111110100100000011101 |
3 | 1201120102110110122122102222 |
4 | 2333121302013310200131 |
5 | 3211000024223404203 |
6 | 43550241445355125 |
7 | 2525165122445201 |
oct | 277316207644035 |
9 | 51512413578388 |
10 | 13153104513053 |
11 | 421122266250a |
12 | 15851b0108aa5 |
13 | 745442482b3b |
14 | 336883c26b01 |
15 | 17c220aa2038 |
hex | bf6721f481d |
13153104513053 has 2 divisors, whose sum is σ = 13153104513054. Its totient is φ = 13153104513052.
The previous prime is 13153104513007. The next prime is 13153104513083. The reversal of 13153104513053 is 35031540135131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9805803742084 + 3347300770969 = 3131422^2 + 1829563^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13153104513053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13153104513083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6576552256526 + 6576552256527.
It is an arithmetic number, because the mean of its divisors is an integer number (6576552256527).
Almost surely, 213153104513053 is an apocalyptic number.
It is an amenable number.
13153104513053 is a deficient number, since it is larger than the sum of its proper divisors (1).
13153104513053 is an equidigital number, since it uses as much as digits as its factorization.
13153104513053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 13153104513053 its reverse (35031540135131), we get a palindrome (48184644648184).
The spelling of 13153104513053 in words is "thirteen trillion, one hundred fifty-three billion, one hundred four million, five hundred thirteen thousand, fifty-three".
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