131531113001 has 2 divisors, whose sum is σ = 131531113002. Its totient is φ = 131531113000.

The previous prime is 131531112971. The next prime is 131531113003. The reversal of 131531113001 is 100311135131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70312477225 + 61218635776 = 265165^2 + 247424^2 .

It is a cyclic number.

It is not a de Polignac number, because 131531113001 - 2³⁴ = 114351243817 is a prime.

Together with 131531113003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131531113003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65765556500 + 65765556501.

It is an arithmetic number, because the mean of its divisors is an integer number (65765556501).

Almost surely, 2^131531113001 is an apocalyptic number.

It is an amenable number.

131531113001 is a deficient number, since it is larger than the sum of its proper divisors (1).

131531113001 is an equidigital number, since it uses as much as digits as its factorization.

131531113001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135, while the sum is 20.

Adding to 131531113001 its reverse (100311135131), we get a palindrome (231842248132).

The spelling of 131531113001 in words is "one hundred thirty-one billion, five hundred thirty-one million, one hundred thirteen thousand, one".