Base | Representation |
---|---|
bin | 11000011111111111… |
… | …01011011011100001 |
3 | 1020221200011111011211 |
4 | 30033333223123201 |
5 | 203414213044324 |
6 | 10013103510121 |
7 | 643643543434 |
oct | 141777533341 |
9 | 36850144154 |
10 | 13153253089 |
11 | 563a7397a9 |
12 | 2670bb8341 |
13 | 131806c4c2 |
14 | 8cac5d81b |
15 | 51eb25294 |
hex | 30ffeb6e1 |
13153253089 has 2 divisors, whose sum is σ = 13153253090. Its totient is φ = 13153253088.
The previous prime is 13153253083. The next prime is 13153253143. The reversal of 13153253089 is 98035235131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9976014400 + 3177238689 = 99880^2 + 56367^2 .
It is an emirp because it is prime and its reverse (98035235131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13153253089 - 27 = 13153252961 is a prime.
It is not a weakly prime, because it can be changed into another prime (13153253083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6576626544 + 6576626545.
It is an arithmetic number, because the mean of its divisors is an integer number (6576626545).
Almost surely, 213153253089 is an apocalyptic number.
It is an amenable number.
13153253089 is a deficient number, since it is larger than the sum of its proper divisors (1).
13153253089 is an equidigital number, since it uses as much as digits as its factorization.
13153253089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 13153253089 in words is "thirteen billion, one hundred fifty-three million, two hundred fifty-three thousand, eighty-nine".
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