Base | Representation |
---|---|
bin | 11000011111111111… |
… | …01011011100010111 |
3 | 1020221200011111020211 |
4 | 30033333223130113 |
5 | 203414213100033 |
6 | 10013103510251 |
7 | 643643543542 |
oct | 141777533427 |
9 | 36850144224 |
10 | 13153253143 |
11 | 563a739848 |
12 | 2670bb8387 |
13 | 131806c534 |
14 | 8cac5d859 |
15 | 51eb252cd |
hex | 30ffeb717 |
13153253143 has 2 divisors, whose sum is σ = 13153253144. Its totient is φ = 13153253142.
The previous prime is 13153253089. The next prime is 13153253147. The reversal of 13153253143 is 34135235131.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (34135235131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13153253143 - 229 = 12616382231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13153253147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6576626571 + 6576626572.
It is an arithmetic number, because the mean of its divisors is an integer number (6576626572).
Almost surely, 213153253143 is an apocalyptic number.
13153253143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13153253143 is an equidigital number, since it uses as much as digits as its factorization.
13153253143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16200, while the sum is 31.
Adding to 13153253143 its reverse (34135235131), we get a palindrome (47288488274).
The spelling of 13153253143 in words is "thirteen billion, one hundred fifty-three million, two hundred fifty-three thousand, one hundred forty-three".
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