131533141503541 has 4 divisors (see below), whose sum is σ = 138455938424800. Its totient is φ = 124610344582284.

The previous prime is 131533141503487. The next prime is 131533141503563. The reversal of 131533141503541 is 145305141335131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131533141503541 - 2¹⁷ = 131533141372469 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131533141503494 and 131533141503503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131533141503241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3461398460601 + ... + 3461398460638.

It is an arithmetic number, because the mean of its divisors is an integer number (34613984606200).

Almost surely, 2^{131533141503541} is an apocalyptic number.

It is an amenable number.

131533141503541 is a deficient number, since it is larger than the sum of its proper divisors (6922796921259).

131533141503541 is an equidigital number, since it uses as much as digits as its factorization.

131533141503541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6922796921258.

The product of its (nonzero) digits is 162000, while the sum is 40.

Adding to 131533141503541 its reverse (145305141335131), we get a palindrome (276838282838672).

The spelling of 131533141503541 in words is "one hundred thirty-one trillion, five hundred thirty-three billion, one hundred forty-one million, five hundred three thousand, five hundred forty-one".