13153442441 has 2 divisors, whose sum is σ = 13153442442. Its totient is φ = 13153442440.

The previous prime is 13153442411. The next prime is 13153442461. The reversal of 13153442441 is 14424435131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11357378041 + 1796064400 = 106571^2 + 42380^2 .

It is a cyclic number.

It is not a de Polignac number, because 13153442441 - 2¹⁴ = 13153426057 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13153442398 and 13153442407.

It is not a weakly prime, because it can be changed into another prime (13153442411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6576721220 + 6576721221.

It is an arithmetic number, because the mean of its divisors is an integer number (6576721221).

Almost surely, 2^13153442441 is an apocalyptic number.

It is an amenable number.

13153442441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13153442441 is an equidigital number, since it uses as much as digits as its factorization.

13153442441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 23040, while the sum is 32.

Adding to 13153442441 its reverse (14424435131), we get a palindrome (27577877572).

The spelling of 13153442441 in words is "thirteen billion, one hundred fifty-three million, four hundred forty-two thousand, four hundred forty-one".