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131537646257 is a prime number
BaseRepresentation
bin111101010000001000…
…0010011001010110001
3110120112002021202202012
41322200100103022301
54123342114140012
6140232204132305
712334424355023
oct1724020231261
9416462252665
10131537646257
115086a632566
12215ab837095
13c5336181a4
14651b7ac013
15364cd47622
hex1ea04132b1

131537646257 has 2 divisors, whose sum is σ = 131537646258. Its totient is φ = 131537646256.

The previous prime is 131537646221. The next prime is 131537646259. The reversal of 131537646257 is 752646735131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127952151616 + 3585494641 = 357704^2 + 59879^2 .

It is an emirp because it is prime and its reverse (752646735131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131537646257 - 234 = 114357777073 is a prime.

It is a super-2 number, since 2×1315376462572 (a number of 23 digits) contains 22 as substring.

Together with 131537646259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131537646259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65768823128 + 65768823129.

It is an arithmetic number, because the mean of its divisors is an integer number (65768823129).

Almost surely, 2131537646257 is an apocalyptic number.

It is an amenable number.

131537646257 is a deficient number, since it is larger than the sum of its proper divisors (1).

131537646257 is an equidigital number, since it uses as much as digits as its factorization.

131537646257 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3175200, while the sum is 50.

The spelling of 131537646257 in words is "one hundred thirty-one billion, five hundred thirty-seven million, six hundred forty-six thousand, two hundred fifty-seven".