Base | Representation |
---|---|
bin | 11101111010001010010010… |
… | …110010100011001110101011 |
3 | 122020202010001220110011201212 |
4 | 131322022102302203032223 |
5 | 114220123142032213311 |
6 | 1143432411345103335 |
7 | 36464314034266025 |
oct | 3572122262431653 |
9 | 566663056404655 |
10 | 131540131132331 |
11 | 38a04946864289 |
12 | 12905437927b4b |
13 | 5852247c7502c |
14 | 246a80d5ad015 |
15 | 10319d9bcdc8b |
hex | 77a292ca33ab |
131540131132331 has 2 divisors, whose sum is σ = 131540131132332. Its totient is φ = 131540131132330.
The previous prime is 131540131132307. The next prime is 131540131132433. The reversal of 131540131132331 is 133231131045131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131540131132331 is a prime.
It is a super-2 number, since 2×1315401311323312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131540137132331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65770065566165 + 65770065566166.
It is an arithmetic number, because the mean of its divisors is an integer number (65770065566166).
Almost surely, 2131540131132331 is an apocalyptic number.
131540131132331 is a deficient number, since it is larger than the sum of its proper divisors (1).
131540131132331 is an equidigital number, since it uses as much as digits as its factorization.
131540131132331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9720, while the sum is 32.
Adding to 131540131132331 its reverse (133231131045131), we get a palindrome (264771262177462).
The spelling of 131540131132331 in words is "one hundred thirty-one trillion, five hundred forty billion, one hundred thirty-one million, one hundred thirty-two thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.115 sec. • engine limits •