131540131132433 has 2 divisors, whose sum is σ = 131540131132434. Its totient is φ = 131540131132432.

The previous prime is 131540131132331. The next prime is 131540131132453. The reversal of 131540131132433 is 334231131045131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131253041991184 + 287089141249 = 11456572^2 + 535807^2 .

It is a cyclic number.

It is not a de Polignac number, because 131540131132433 - 2¹⁸ = 131540130870289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131540131132393 and 131540131132402.

It is not a weakly prime, because it can be changed into another prime (131540131132453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65770065566216 + 65770065566217.

It is an arithmetic number, because the mean of its divisors is an integer number (65770065566217).

Almost surely, 2^{131540131132433} is an apocalyptic number.

It is an amenable number.

131540131132433 is a deficient number, since it is larger than the sum of its proper divisors (1).

131540131132433 is an equidigital number, since it uses as much as digits as its factorization.

131540131132433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38880, while the sum is 35.

Adding to 131540131132433 its reverse (334231131045131), we get a palindrome (465771262177564).

The spelling of 131540131132433 in words is "one hundred thirty-one trillion, five hundred forty billion, one hundred thirty-one million, one hundred thirty-two thousand, four hundred thirty-three".