Base | Representation |
---|---|
bin | 10011001001000100100… |
… | …110111101001110101111 |
3 | 11122202022020222012002210 |
4 | 103021010212331032233 |
5 | 133022430212234120 |
6 | 2444142544021503 |
7 | 164015053326423 |
oct | 23110446751657 |
9 | 4582266865083 |
10 | 1315411055535 |
11 | 467954280325 |
12 | 192b28601893 |
13 | 97072b55c05 |
14 | 47948210b83 |
15 | 2433bd83ce0 |
hex | 132449bd3af |
1315411055535 has 16 divisors (see below), whose sum is σ = 2177232092640. Its totient is φ = 677361095040.
The previous prime is 1315411055527. The next prime is 1315411055573. The reversal of 1315411055535 is 5355501145131.
It is not a de Polignac number, because 1315411055535 - 23 = 1315411055527 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1315411055493 and 1315411055502.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1511966296 + ... + 1511967165.
It is an arithmetic number, because the mean of its divisors is an integer number (136077005790).
Almost surely, 21315411055535 is an apocalyptic number.
1315411055535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1315411055535 is a deficient number, since it is larger than the sum of its proper divisors (861821037105).
1315411055535 is a wasteful number, since it uses less digits than its factorization.
1315411055535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3023933498.
The product of its (nonzero) digits is 112500, while the sum is 39.
The spelling of 1315411055535 in words is "one trillion, three hundred fifteen billion, four hundred eleven million, fifty-five thousand, five hundred thirty-five".
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