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131542052055457 is a prime number
BaseRepresentation
bin11101111010001100000101…
…010010010010100110100001
3122020202022000210000011212211
4131322030011102102212201
5114220141110311233312
61143433330125122121
736464412451001011
oct3572140522224641
9566668023004784
10131542052055457
1138a0574210025a
12129058930b9341
135852492c23234
14246a952761c41
151031a9d6713a7
hex77a3054929a1

131542052055457 has 2 divisors, whose sum is σ = 131542052055458. Its totient is φ = 131542052055456.

The previous prime is 131542052055431. The next prime is 131542052055481. The reversal of 131542052055457 is 754550250245131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129807376036416 + 1734676019041 = 11393304^2 + 1317071^2 .

It is a cyclic number.

It is not a de Polignac number, because 131542052055457 - 211 = 131542052053409 is a prime.

It is a super-2 number, since 2×1315420520554572 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131542052055457.

It is not a weakly prime, because it can be changed into another prime (131542052053457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65771026027728 + 65771026027729.

It is an arithmetic number, because the mean of its divisors is an integer number (65771026027729).

Almost surely, 2131542052055457 is an apocalyptic number.

It is an amenable number.

131542052055457 is a deficient number, since it is larger than the sum of its proper divisors (1).

131542052055457 is an equidigital number, since it uses as much as digits as its factorization.

131542052055457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4200000, while the sum is 49.

The spelling of 131542052055457 in words is "one hundred thirty-one trillion, five hundred forty-two billion, fifty-two million, fifty-five thousand, four hundred fifty-seven".