Base | Representation |
---|---|
bin | 11101111010001100000101… |
… | …010010010010100110000111 |
3 | 122020202022000210000011211212 |
4 | 131322030011102102212013 |
5 | 114220141110311233211 |
6 | 1143433330125122035 |
7 | 36464412451000643 |
oct | 3572140522224607 |
9 | 566668023004755 |
10 | 131542052055431 |
11 | 38a05742100236 |
12 | 129058930b931b |
13 | 5852492c23214 |
14 | 246a952761c23 |
15 | 1031a9d67138b |
hex | 77a305492987 |
131542052055431 has 2 divisors, whose sum is σ = 131542052055432. Its totient is φ = 131542052055430.
The previous prime is 131542052055377. The next prime is 131542052055457. The reversal of 131542052055431 is 134550250245131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131542052055431 is a prime.
It is a super-2 number, since 2×1315420520554312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131542052055481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65771026027715 + 65771026027716.
It is an arithmetic number, because the mean of its divisors is an integer number (65771026027716).
Almost surely, 2131542052055431 is an apocalyptic number.
131542052055431 is a deficient number, since it is larger than the sum of its proper divisors (1).
131542052055431 is an equidigital number, since it uses as much as digits as its factorization.
131542052055431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360000, while the sum is 41.
The spelling of 131542052055431 in words is "one hundred thirty-one trillion, five hundred forty-two billion, fifty-two million, fifty-five thousand, four hundred thirty-one".
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