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1315423555541 = 4313052026811
BaseRepresentation
bin10011001001000101010…
…110101000111111010101
311122202100010111020212222
4103021011112220333111
5133022441412234131
62444144111552125
7164015264510534
oct23110526507725
94582303436788
101315423555541
11467960338807
12192b3082b645
1397075611674
1447949b4631b
152433d00287b
hex132455a8fd5

1315423555541 has 4 divisors (see below), whose sum is σ = 1318475582784. Its totient is φ = 1312371528300.

The previous prime is 1315423555529. The next prime is 1315423555561. The reversal of 1315423555541 is 1455553245131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1315423555541 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1315423555492 and 1315423555501.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1315423555561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1526012975 + ... + 1526013836.

It is an arithmetic number, because the mean of its divisors is an integer number (329618895696).

Almost surely, 21315423555541 is an apocalyptic number.

It is an amenable number.

1315423555541 is a deficient number, since it is larger than the sum of its proper divisors (3052027243).

1315423555541 is an equidigital number, since it uses as much as digits as its factorization.

1315423555541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3052027242.

The product of its digits is 900000, while the sum is 44.

The spelling of 1315423555541 in words is "one trillion, three hundred fifteen billion, four hundred twenty-three million, five hundred fifty-five thousand, five hundred forty-one".

Divisors: 1 431 3052026811 1315423555541