Base | Representation |
---|---|
bin | 1011111101101011011000… |
… | …0110111001111110110111 |
3 | 1201120112101221220200112201 |
4 | 2333122312012321332313 |
5 | 3211004343222432043 |
6 | 43550550552525331 |
7 | 2525235312462463 |
oct | 277326606717667 |
9 | 51515357820481 |
10 | 13154245124023 |
11 | 4211758495403 |
12 | 158546a0b0847 |
13 | 745594882483 |
14 | 3369514d74a3 |
15 | 17c28acaac4d |
hex | bf6b61b9fb7 |
13154245124023 has 2 divisors, whose sum is σ = 13154245124024. Its totient is φ = 13154245124022.
The previous prime is 13154245123967. The next prime is 13154245124047. The reversal of 13154245124023 is 32042154245131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13154245124023 - 225 = 13154211569591 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13154245124123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577122562011 + 6577122562012.
It is an arithmetic number, because the mean of its divisors is an integer number (6577122562012).
Almost surely, 213154245124023 is an apocalyptic number.
13154245124023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154245124023 is an equidigital number, since it uses as much as digits as its factorization.
13154245124023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 13154245124023 its reverse (32042154245131), we get a palindrome (45196399369154).
The spelling of 13154245124023 in words is "thirteen trillion, one hundred fifty-four billion, two hundred forty-five million, one hundred twenty-four thousand, twenty-three".
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