Base | Representation |
---|---|
bin | 1011111101101011011000… |
… | …1000011001001110011111 |
3 | 1201120112101222122111200121 |
4 | 2333122312020121032133 |
5 | 3211004343322423033 |
6 | 43550551005135411 |
7 | 2525235316006036 |
oct | 277326610311637 |
9 | 51515358574617 |
10 | 13154245514143 |
11 | 4211758731518 |
12 | 158546a25a567 |
13 | 74559498ac06 |
14 | 33695159971d |
15 | 17c28ad3662d |
hex | bf6b621939f |
13154245514143 has 2 divisors, whose sum is σ = 13154245514144. Its totient is φ = 13154245514142.
The previous prime is 13154245514131. The next prime is 13154245514183. The reversal of 13154245514143 is 34141554245131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13154245514143 - 29 = 13154245513631 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13154245514143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13154245514183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577122757071 + 6577122757072.
It is an arithmetic number, because the mean of its divisors is an integer number (6577122757072).
Almost surely, 213154245514143 is an apocalyptic number.
13154245514143 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154245514143 is an equidigital number, since it uses as much as digits as its factorization.
13154245514143 is an evil number, because the sum of its binary digits is even.
The product of its digits is 576000, while the sum is 43.
Adding to 13154245514143 its reverse (34141554245131), we get a palindrome (47295799759274).
The spelling of 13154245514143 in words is "thirteen trillion, one hundred fifty-four billion, two hundred forty-five million, five hundred fourteen thousand, one hundred forty-three".
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