Base | Representation |
---|---|
bin | 10011001001000101100… |
… | …000111001101000001011 |
3 | 11122202100022112220022102 |
4 | 103021011200321220023 |
5 | 133022443104321011 |
6 | 2444144245344015 |
7 | 164015326412105 |
oct | 23110540715013 |
9 | 4582308486272 |
10 | 1315426245131 |
11 | 467961905509 |
12 | 192b3170800b |
13 | 9707604393b |
14 | 4794a246575 |
15 | 2433d38473b |
hex | 13245839a0b |
1315426245131 has 2 divisors, whose sum is σ = 1315426245132. Its totient is φ = 1315426245130.
The previous prime is 1315426245083. The next prime is 1315426245227.
1315426245131 is nontrivially palindromic in base 10.
It is a weak prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 1315426245131 - 210 = 1315426244107 is a prime.
It is a super-2 number, since 2×13154262451312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1315426245031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657713122565 + 657713122566.
It is an arithmetic number, because the mean of its divisors is an integer number (657713122566).
Almost surely, 21315426245131 is an apocalyptic number.
1315426245131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1315426245131 is an equidigital number, since it uses as much as digits as its factorization.
1315426245131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 86400, while the sum is 38.
The spelling of 1315426245131 in words is "one trillion, three hundred fifteen billion, four hundred twenty-six million, two hundred forty-five thousand, one hundred thirty-one".
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