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1315483537 is a prime number
BaseRepresentation
bin100111001101000…
…1010111110010001
310101200022111011111
41032122022332101
510143230433122
6334311213321
744412265654
oct11632127621
93350274144
101315483537
11615613285
12308677241
1317c6c9734
14c69d189b
157a74cd77
hex4e68af91

1315483537 has 2 divisors, whose sum is σ = 1315483538. Its totient is φ = 1315483536.

The previous prime is 1315483451. The next prime is 1315483553. The reversal of 1315483537 is 7353845131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 692531856 + 622951681 = 26316^2 + 24959^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1315483537 is a prime.

It is a super-2 number, since 2×13154835372 = 3460993872236060738, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1315483537.

It is not a weakly prime, because it can be changed into another prime (1315483577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 657741768 + 657741769.

It is an arithmetic number, because the mean of its divisors is an integer number (657741769).

Almost surely, 21315483537 is an apocalyptic number.

It is an amenable number.

1315483537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1315483537 is an equidigital number, since it uses as much as digits as its factorization.

1315483537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 151200, while the sum is 40.

The square root of 1315483537 is about 36269.5952141735. The cubic root of 1315483537 is about 1095.7087734873.

The spelling of 1315483537 in words is "one billion, three hundred fifteen million, four hundred eighty-three thousand, five hundred thirty-seven".