Base | Representation |
---|---|
bin | 1011111101101111001000… |
… | …0111111010111111001101 |
3 | 1201120122000010120110121111 |
4 | 2333123302013322333031 |
5 | 3211013424004220440 |
6 | 43551234522132021 |
7 | 2525302260126643 |
oct | 277336207727715 |
9 | 51518003513544 |
10 | 13155252023245 |
11 | 42121248a0722 |
12 | 15856ab351011 |
13 | 7456c5366a27 |
14 | 336a0911d193 |
15 | 17c2e93a14ea |
hex | bf6f21fafcd |
13155252023245 has 16 divisors (see below), whose sum is σ = 16172178378048. Its totient is φ = 10266977784960.
The previous prime is 13155252023239. The next prime is 13155252023261. The reversal of 13155252023245 is 54232025255131.
It is not a de Polignac number, because 13155252023245 - 213 = 13155252015053 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13155252023198 and 13155252023207.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2284402 + ... + 5615068.
It is an arithmetic number, because the mean of its divisors is an integer number (1010761148628).
Almost surely, 213155252023245 is an apocalyptic number.
It is an amenable number.
13155252023245 is a deficient number, since it is larger than the sum of its proper divisors (3016926354803).
13155252023245 is a wasteful number, since it uses less digits than its factorization.
13155252023245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3349980.
The product of its (nonzero) digits is 360000, while the sum is 40.
Adding to 13155252023245 its reverse (54232025255131), we get a palindrome (67387277278376).
The spelling of 13155252023245 in words is "thirteen trillion, one hundred fifty-five billion, two hundred fifty-two million, twenty-three thousand, two hundred forty-five".
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