Base | Representation |
---|---|
bin | 1011111101101111011101… |
… | …1100101101101111110011 |
3 | 1201120122020100200020202110 |
4 | 2333123313130231233303 |
5 | 3211014114342010430 |
6 | 43551251433020403 |
7 | 2525304423361203 |
oct | 277336734555763 |
9 | 51518210606673 |
10 | 13155341360115 |
11 | 4212170269849 |
12 | 1585715254703 |
13 | 74570aa15b96 |
14 | 336a16d36403 |
15 | 17c30214b7b0 |
hex | bf6f772dbf3 |
13155341360115 has 8 divisors (see below), whose sum is σ = 21048546176208. Its totient is φ = 7016182058720.
The previous prime is 13155341360099. The next prime is 13155341360129. The reversal of 13155341360115 is 51106314355131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13155341360115 - 24 = 13155341360099 is a prime.
It is a super-2 number, since 2×131553413601152 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 438511378656 + ... + 438511378685.
It is an arithmetic number, because the mean of its divisors is an integer number (2631068272026).
Almost surely, 213155341360115 is an apocalyptic number.
13155341360115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13155341360115 is a deficient number, since it is larger than the sum of its proper divisors (7893204816093).
13155341360115 is an equidigital number, since it uses as much as digits as its factorization.
13155341360115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 877022757349.
The product of its (nonzero) digits is 81000, while the sum is 39.
The spelling of 13155341360115 in words is "thirteen trillion, one hundred fifty-five billion, three hundred forty-one million, three hundred sixty thousand, one hundred fifteen".
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