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13155455242441 is a prime number
BaseRepresentation
bin1011111101101111111000…
…1111001001000011001001
31201120122112021222001221101
42333123332033021003021
53211014333020224231
643551311021541401
72525310305352511
oct277337617110311
951518467861841
1013155455242441
114212219582276
121585747414861
137457284aa385
14336a280dc841
1517c30c144661
hexbf6fe3c90c9

13155455242441 has 2 divisors, whose sum is σ = 13155455242442. Its totient is φ = 13155455242440.

The previous prime is 13155455242399. The next prime is 13155455242469. The reversal of 13155455242441 is 14424255455131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12415475073600 + 739980168841 = 3523560^2 + 860221^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13155455242441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13155455242391 and 13155455242400.

It is not a weakly prime, because it can be changed into another prime (13155455242841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577727621220 + 6577727621221.

It is an arithmetic number, because the mean of its divisors is an integer number (6577727621221).

Almost surely, 213155455242441 is an apocalyptic number.

It is an amenable number.

13155455242441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13155455242441 is an equidigital number, since it uses as much as digits as its factorization.

13155455242441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1920000, while the sum is 46.

The spelling of 13155455242441 in words is "thirteen trillion, one hundred fifty-five billion, four hundred fifty-five million, two hundred forty-two thousand, four hundred forty-one".