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13155455242841 is a prime number
BaseRepresentation
bin1011111101101111111000…
…1111001001001001011001
31201120122112021222002111012
42333123332033021021121
53211014333020232331
643551311021543305
72525310305353622
oct277337617111131
951518467862435
1013155455242841
1142122195825aa
121585747414b35
137457284aa602
14336a280dca49
1517c30c14482b
hexbf6fe3c9259

13155455242841 has 2 divisors, whose sum is σ = 13155455242842. Its totient is φ = 13155455242840.

The previous prime is 13155455242793. The next prime is 13155455242889. The reversal of 13155455242841 is 14824255455131.

It is a balanced prime because it is at equal distance from previous prime (13155455242793) and next prime (13155455242889).

It can be written as a sum of positive squares in only one way, i.e., 7333827274816 + 5821627968025 = 2708104^2 + 2412805^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13155455242841 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13155455242841.

It is not a weakly prime, because it can be changed into another prime (13155455242441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577727621420 + 6577727621421.

It is an arithmetic number, because the mean of its divisors is an integer number (6577727621421).

Almost surely, 213155455242841 is an apocalyptic number.

It is an amenable number.

13155455242841 is a deficient number, since it is larger than the sum of its proper divisors (1).

13155455242841 is an equidigital number, since it uses as much as digits as its factorization.

13155455242841 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3840000, while the sum is 50.

The spelling of 13155455242841 in words is "thirteen trillion, one hundred fifty-five billion, four hundred fifty-five million, two hundred forty-two thousand, eight hundred forty-one".