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131555003 is a prime number
BaseRepresentation
bin1111101011101…
…01111010111011
3100011112200112112
413311311322323
5232134230003
621015402535
73155125166
oct765657273
9304480475
10131555003
1168294248
123808344b
13213414c8
1413686add
15b8393d8
hex7d75ebb

131555003 has 2 divisors, whose sum is σ = 131555004. Its totient is φ = 131555002.

The previous prime is 131554919. The next prime is 131555023. The reversal of 131555003 is 300555131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131555003 - 28 = 131554747 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131555003.

It is not a weakly prime, because it can be changed into another prime (131555023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65777501 + 65777502.

It is an arithmetic number, because the mean of its divisors is an integer number (65777502).

Almost surely, 2131555003 is an apocalyptic number.

131555003 is a deficient number, since it is larger than the sum of its proper divisors (1).

131555003 is an equidigital number, since it uses as much as digits as its factorization.

131555003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1125, while the sum is 23.

The square root of 131555003 is about 11469.7429352187. The cubic root of 131555003 is about 508.5915296648.

The spelling of 131555003 in words is "one hundred thirty-one million, five hundred fifty-five thousand, three".