Base | Representation |
---|---|
bin | 11000100000010000… |
… | …11011000001110001 |
3 | 1020221211110221100212 |
4 | 30100020123001301 |
5 | 203420304421301 |
6 | 10013224553505 |
7 | 644002201121 |
oct | 142010330161 |
9 | 36854427325 |
10 | 13155545201 |
11 | 5640a64907 |
12 | 2671922895 |
13 | 1318692896 |
14 | 8cb298c81 |
15 | 51ee294bb |
hex | 31021b071 |
13155545201 has 2 divisors, whose sum is σ = 13155545202. Its totient is φ = 13155545200.
The previous prime is 13155545191. The next prime is 13155545203. The reversal of 13155545201 is 10254555131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13154943025 + 602176 = 114695^2 + 776^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13155545201 is a prime.
Together with 13155545203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13155545203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577772600 + 6577772601.
It is an arithmetic number, because the mean of its divisors is an integer number (6577772601).
Almost surely, 213155545201 is an apocalyptic number.
It is an amenable number.
13155545201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13155545201 is an equidigital number, since it uses as much as digits as its factorization.
13155545201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 32.
The spelling of 13155545201 in words is "thirteen billion, one hundred fifty-five million, five hundred forty-five thousand, two hundred one".
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