Base | Representation |
---|---|
bin | 11000100000101110… |
… | …11101000111011101 |
3 | 1020222002220011000022 |
4 | 30100113131013131 |
5 | 203422312022132 |
6 | 10013445241525 |
7 | 644050533104 |
oct | 142027350735 |
9 | 36862804008 |
10 | 13159485917 |
11 | 56432065a6 |
12 | 26731032a5 |
13 | 1319442476 |
14 | 8cba0303b |
15 | 520456e12 |
hex | 3105dd1dd |
13159485917 has 2 divisors, whose sum is σ = 13159485918. Its totient is φ = 13159485916.
The previous prime is 13159485907. The next prime is 13159485929. The reversal of 13159485917 is 71958495131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9454450756 + 3705035161 = 97234^2 + 60869^2 .
It is a cyclic number.
It is not a de Polignac number, because 13159485917 - 24 = 13159485901 is a prime.
It is a super-3 number, since 3×131594859173 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13159485907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6579742958 + 6579742959.
It is an arithmetic number, because the mean of its divisors is an integer number (6579742959).
Almost surely, 213159485917 is an apocalyptic number.
It is an amenable number.
13159485917 is a deficient number, since it is larger than the sum of its proper divisors (1).
13159485917 is an equidigital number, since it uses as much as digits as its factorization.
13159485917 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1360800, while the sum is 53.
The spelling of 13159485917 in words is "thirteen billion, one hundred fifty-nine million, four hundred eighty-five thousand, nine hundred seventeen".
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