13160213526541 has 2 divisors, whose sum is σ = 13160213526542. Its totient is φ = 13160213526540.

The previous prime is 13160213526451. The next prime is 13160213526547. The reversal of 13160213526541 is 14562531206131.

13160213526541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (13160213526451) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8016707041641 + 5143506484900 = 2831379^2 + 2267930^2 .

It is a cyclic number.

It is not a de Polignac number, because 13160213526541 - 2¹³ = 13160213518349 is a prime.

It is a super-2 number, since 2×13160213526541² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13160213526494 and 13160213526503.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13160213526547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6580106763270 + 6580106763271.

It is an arithmetic number, because the mean of its divisors is an integer number (6580106763271).

Almost surely, 2^{13160213526541} is an apocalyptic number.

It is an amenable number.

13160213526541 is a deficient number, since it is larger than the sum of its proper divisors (1).

13160213526541 is an equidigital number, since it uses as much as digits as its factorization.

13160213526541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 40.

The spelling of 13160213526541 in words is "thirteen trillion, one hundred sixty billion, two hundred thirteen million, five hundred twenty-six thousand, five hundred forty-one".