Base | Representation |
---|---|
bin | 1011111110000010100010… |
… | …1110101011011010100011 |
3 | 1201121010110022011121112022 |
4 | 2333200220232223122203 |
5 | 3211110112024320120 |
6 | 43553455554052055 |
7 | 2525545354536650 |
oct | 277405056533243 |
9 | 51533408147468 |
10 | 13160463120035 |
11 | 421435937a890 |
12 | 158670457a02b |
13 | 746045b6675a |
14 | 336d81250c27 |
15 | 17c501b05025 |
hex | bf828bab6a3 |
13160463120035 has 16 divisors (see below), whose sum is σ = 19689420148992. Its totient is φ = 8203925061600.
The previous prime is 13160463119981. The next prime is 13160463120067. The reversal of 13160463120035 is 53002136406131.
It is not a de Polignac number, because 13160463120035 - 212 = 13160463115939 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a junction number, because it is equal to n+sod(n) for n = 13160463119977 and 13160463120004.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17091510161 + ... + 17091510930.
It is an arithmetic number, because the mean of its divisors is an integer number (1230588759312).
Almost surely, 213160463120035 is an apocalyptic number.
13160463120035 is a deficient number, since it is larger than the sum of its proper divisors (6528957028957).
13160463120035 is a wasteful number, since it uses less digits than its factorization.
13160463120035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34183021114.
The product of its (nonzero) digits is 38880, while the sum is 35.
Adding to 13160463120035 its reverse (53002136406131), we get a palindrome (66162599526166).
The spelling of 13160463120035 in words is "thirteen trillion, one hundred sixty billion, four hundred sixty-three million, one hundred twenty thousand, thirty-five".
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