Base | Representation |
---|---|
bin | 10011001001101010110… |
… | …100000100010000010101 |
3 | 11122210221221001212211001 |
4 | 103021222310010100111 |
5 | 133030233304321024 |
6 | 2444330322143301 |
7 | 164036665436212 |
oct | 23115264042025 |
9 | 4583857055731 |
10 | 1316052026389 |
11 | 468153072201 |
12 | 1930871b1b31 |
13 | 971458981c9 |
14 | 479a93c0b09 |
15 | 24378296244 |
hex | 1326ad04415 |
1316052026389 has 2 divisors, whose sum is σ = 1316052026390. Its totient is φ = 1316052026388.
The previous prime is 1316052026371. The next prime is 1316052026501. The reversal of 1316052026389 is 9836202506131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1008132467364 + 307919559025 = 1004058^2 + 554905^2 .
It is an emirp because it is prime and its reverse (9836202506131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1316052026389 - 217 = 1316051895317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1316052023389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658026013194 + 658026013195.
It is an arithmetic number, because the mean of its divisors is an integer number (658026013195).
Almost surely, 21316052026389 is an apocalyptic number.
It is an amenable number.
1316052026389 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316052026389 is an equidigital number, since it uses as much as digits as its factorization.
1316052026389 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 466560, while the sum is 46.
The spelling of 1316052026389 in words is "one trillion, three hundred sixteen billion, fifty-two million, twenty-six thousand, three hundred eighty-nine".
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