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13161214433 = 47280025839
BaseRepresentation
bin11000100000111100…
…00011000111100001
31020222020010222002102
430100132003013201
5203423232330213
610013550300145
7644101322363
oct142036030741
936866128072
1013161214433
115644187224
1226737b7655
1313198c9163
148cbd32d33
15520699158
hex3107831e1

13161214433 has 4 divisors (see below), whose sum is σ = 13441240320. Its totient is φ = 12881188548.

The previous prime is 13161214403. The next prime is 13161214439. The reversal of 13161214433 is 33441216131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13161214433 - 26 = 13161214369 is a prime.

It is a super-2 number, since 2×131612144332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13161214396 and 13161214405.

It is not an unprimeable number, because it can be changed into a prime (13161214439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 140012873 + ... + 140012966.

It is an arithmetic number, because the mean of its divisors is an integer number (3360310080).

Almost surely, 213161214433 is an apocalyptic number.

It is an amenable number.

13161214433 is a deficient number, since it is larger than the sum of its proper divisors (280025887).

13161214433 is an equidigital number, since it uses as much as digits as its factorization.

13161214433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 280025886.

The product of its digits is 5184, while the sum is 29.

The spelling of 13161214433 in words is "thirteen billion, one hundred sixty-one million, two hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 47 280025839 13161214433