Base | Representation |
---|---|
bin | 10011001001110000001… |
… | …110100110001111011011 |
3 | 11122211012021000002021122 |
4 | 103021300032212033123 |
5 | 133030430033224134 |
6 | 2444343325155455 |
7 | 164042150533652 |
oct | 23116016461733 |
9 | 4584167002248 |
10 | 1316142867419 |
11 | 46819a378436 |
12 | 1930b16bbb8b |
13 | 9715b652bb3 |
14 | 479b74aa199 |
15 | 2438123c02e |
hex | 132703a63db |
1316142867419 has 2 divisors, whose sum is σ = 1316142867420. Its totient is φ = 1316142867418.
The previous prime is 1316142867409. The next prime is 1316142867421. The reversal of 1316142867419 is 9147682416131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1316142867419 is a prime.
It is a super-2 number, since 2×13161428674192 (a number of 25 digits) contains 22 as substring.
Together with 1316142867421, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1316142867409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658071433709 + 658071433710.
It is an arithmetic number, because the mean of its divisors is an integer number (658071433710).
Almost surely, 21316142867419 is an apocalyptic number.
1316142867419 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316142867419 is an equidigital number, since it uses as much as digits as its factorization.
1316142867419 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1741824, while the sum is 53.
The spelling of 1316142867419 in words is "one trillion, three hundred sixteen billion, one hundred forty-two million, eight hundred sixty-seven thousand, four hundred nineteen".
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