Base | Representation |
---|---|
bin | 10011001001110010001… |
… | …110100110001111000111 |
3 | 11122211021121010211021122 |
4 | 103021302032212033013 |
5 | 133031012130444311 |
6 | 2444350524304155 |
7 | 164043035665145 |
oct | 23116216461707 |
9 | 4584247124248 |
10 | 1316176421831 |
11 | 468207306357 |
12 | 1931009a205b |
13 | 971655a098b |
14 | 479bbb22595 |
15 | 243841690db |
hex | 132723a63c7 |
1316176421831 has 2 divisors, whose sum is σ = 1316176421832. Its totient is φ = 1316176421830.
The previous prime is 1316176421773. The next prime is 1316176421839. The reversal of 1316176421831 is 1381246716131.
It is a strong prime.
It is an emirp because it is prime and its reverse (1381246716131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1316176421831 - 26 = 1316176421767 is a prime.
It is a super-2 number, since 2×13161764218312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1316176421839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658088210915 + 658088210916.
It is an arithmetic number, because the mean of its divisors is an integer number (658088210916).
Almost surely, 21316176421831 is an apocalyptic number.
1316176421831 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316176421831 is an equidigital number, since it uses as much as digits as its factorization.
1316176421831 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 145152, while the sum is 44.
The spelling of 1316176421831 in words is "one trillion, three hundred sixteen billion, one hundred seventy-six million, four hundred twenty-one thousand, eight hundred thirty-one".
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