Base | Representation |
---|---|
bin | 10011001001110101101… |
… | …000111100100000111101 |
3 | 11122211102120211211221111 |
4 | 103021311220330200331 |
5 | 133031121304113402 |
6 | 2444400331202021 |
7 | 164044332341521 |
oct | 23116550744075 |
9 | 4584376754844 |
10 | 1316233660477 |
11 | 46823665061a |
12 | 193117ba6311 |
13 | 971743c1ab8 |
14 | 479c5581d81 |
15 | 243891c39d7 |
hex | 13275a3c83d |
1316233660477 has 2 divisors, whose sum is σ = 1316233660478. Its totient is φ = 1316233660476.
The previous prime is 1316233660349. The next prime is 1316233660493. The reversal of 1316233660477 is 7740663326131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1311789971556 + 4443688921 = 1145334^2 + 66661^2 .
It is a cyclic number.
It is not a de Polignac number, because 1316233660477 - 27 = 1316233660349 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1316233660477.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1316233666477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658116830238 + 658116830239.
It is an arithmetic number, because the mean of its divisors is an integer number (658116830239).
Almost surely, 21316233660477 is an apocalyptic number.
It is an amenable number.
1316233660477 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316233660477 is an equidigital number, since it uses as much as digits as its factorization.
1316233660477 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2286144, while the sum is 49.
The spelling of 1316233660477 in words is "one trillion, three hundred sixteen billion, two hundred thirty-three million, six hundred sixty thousand, four hundred seventy-seven".
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