Base | Representation |
---|---|
bin | 1011111110001100001110… |
… | …1100111110111001111111 |
3 | 1201121101011111120111222112 |
4 | 2333203003230332321333 |
5 | 3211130423131102223 |
6 | 43555005553404235 |
7 | 2525666655430640 |
oct | 277430354767177 |
9 | 51541144514875 |
10 | 13163063144063 |
11 | 4215472a91378 |
12 | 158710b26967b |
13 | 74636b717601 |
14 | 33714a69b6c7 |
15 | 17c604edc778 |
hex | bf8c3b3ee7f |
13163063144063 has 4 divisors (see below), whose sum is σ = 15043500736080. Its totient is φ = 11282625552048.
The previous prime is 13163063144059. The next prime is 13163063144089. The reversal of 13163063144063 is 36044136036131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13163063144063 - 22 = 13163063144059 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13163063144063.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13163063144003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 940218795998 + ... + 940218796011.
It is an arithmetic number, because the mean of its divisors is an integer number (3760875184020).
Almost surely, 213163063144063 is an apocalyptic number.
13163063144063 is a deficient number, since it is larger than the sum of its proper divisors (1880437592017).
13163063144063 is an equidigital number, since it uses as much as digits as its factorization.
13163063144063 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1880437592016.
The product of its (nonzero) digits is 279936, while the sum is 41.
The spelling of 13163063144063 in words is "thirteen trillion, one hundred sixty-three billion, sixty-three million, one hundred forty-four thousand, sixty-three".
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