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1316412262093 is a prime number
BaseRepresentation
bin10011001010000000010…
…010010000011011001101
311122211220000220202022011
4103022000102100123031
5133032003014341333
62444430151221221
7164051631414115
oct23120022203315
94584800822264
101316412262093
11468318448665
12193167977811
13971a23c6326
1447a01194045
1524399c029cd
hex132804906cd

1316412262093 has 2 divisors, whose sum is σ = 1316412262094. Its totient is φ = 1316412262092.

The previous prime is 1316412262037. The next prime is 1316412262127. The reversal of 1316412262093 is 3902622146131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 912441427524 + 403970834569 = 955218^2 + 635587^2 .

It is a cyclic number.

It is not a de Polignac number, because 1316412262093 - 225 = 1316378707661 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1316412262493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658206131046 + 658206131047.

It is an arithmetic number, because the mean of its divisors is an integer number (658206131047).

Almost surely, 21316412262093 is an apocalyptic number.

It is an amenable number.

1316412262093 is a deficient number, since it is larger than the sum of its proper divisors (1).

1316412262093 is an equidigital number, since it uses as much as digits as its factorization.

1316412262093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 40.

The spelling of 1316412262093 in words is "one trillion, three hundred sixteen billion, four hundred twelve million, two hundred sixty-two thousand, ninety-three".