Base | Representation |
---|---|
bin | 11101111011101010001000… |
… | …001111001010110101110101 |
3 | 122021002221200100000221001122 |
4 | 131323222020033022311311 |
5 | 114223314413011102331 |
6 | 1143551550303433325 |
7 | 36504616041264533 |
oct | 3573521017126565 |
9 | 567087610027048 |
10 | 131643033300341 |
11 | 38a4455140a142 |
12 | 129213755b5845 |
13 | 585bb66b04244 |
14 | 24717b1c4b153 |
15 | 103450dad517b |
hex | 77ba883cad75 |
131643033300341 has 2 divisors, whose sum is σ = 131643033300342. Its totient is φ = 131643033300340.
The previous prime is 131643033300307. The next prime is 131643033300367. The reversal of 131643033300341 is 143003330346131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110549873632900 + 21093159667441 = 10514270^2 + 4592729^2 .
It is a cyclic number.
It is not a de Polignac number, because 131643033300341 - 246 = 61274289122677 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131643033300301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65821516650170 + 65821516650171.
It is an arithmetic number, because the mean of its divisors is an integer number (65821516650171).
Almost surely, 2131643033300341 is an apocalyptic number.
It is an amenable number.
131643033300341 is a deficient number, since it is larger than the sum of its proper divisors (1).
131643033300341 is an equidigital number, since it uses as much as digits as its factorization.
131643033300341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69984, while the sum is 35.
Adding to 131643033300341 its reverse (143003330346131), we get a palindrome (274646363646472).
The spelling of 131643033300341 in words is "one hundred thirty-one trillion, six hundred forty-three billion, thirty-three million, three hundred thousand, three hundred forty-one".
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