Base | Representation |
---|---|
bin | 111101010011010001… |
… | …0100111011111101111 |
3 | 110120210102201221201212 |
4 | 1322212202213133233 |
5 | 4124101114031112 |
6 | 140250452425035 |
7 | 12340144661423 |
oct | 1724642473757 |
9 | 416712657655 |
10 | 131643111407 |
11 | 50914117045 |
12 | 2161b01817b |
13 | c54c4233c2 |
14 | 652b7c2b83 |
15 | 365722b522 |
hex | 1ea68a77ef |
131643111407 has 2 divisors, whose sum is σ = 131643111408. Its totient is φ = 131643111406.
The previous prime is 131643111337. The next prime is 131643111419. The reversal of 131643111407 is 704111346131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131643111407 - 216 = 131643045871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131643111707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65821555703 + 65821555704.
It is an arithmetic number, because the mean of its divisors is an integer number (65821555704).
Almost surely, 2131643111407 is an apocalyptic number.
131643111407 is a deficient number, since it is larger than the sum of its proper divisors (1).
131643111407 is an equidigital number, since it uses as much as digits as its factorization.
131643111407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 32.
Adding to 131643111407 its reverse (704111346131), we get a palindrome (835754457538).
The spelling of 131643111407 in words is "one hundred thirty-one billion, six hundred forty-three million, one hundred eleven thousand, four hundred seven".
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