Base | Representation |
---|---|
bin | 1011111110010000111110… |
… | …0000101110110000011010 |
3 | 1201121111110010210112011021 |
4 | 2333210033200232300122 |
5 | 3211141024230004402 |
6 | 43555340105553054 |
7 | 2526043331144332 |
oct | 277441740566032 |
9 | 51544403715137 |
10 | 13164335000602 |
11 | 4215a65a06a85 |
12 | 15874051a578a |
13 | 74651207a646 |
14 | 33722b5740c2 |
15 | 17c67b9bdd37 |
hex | bf90f82ec1a |
13164335000602 has 4 divisors (see below), whose sum is σ = 19746502500906. Its totient is φ = 6582167500300.
The previous prime is 13164335000563. The next prime is 13164335000623. The reversal of 13164335000602 is 20600053346131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13133006354601 + 31328646001 = 3623949^2 + 176999^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3291083750149 + ... + 3291083750152.
Almost surely, 213164335000602 is an apocalyptic number.
13164335000602 is a deficient number, since it is larger than the sum of its proper divisors (6582167500304).
13164335000602 is an equidigital number, since it uses as much as digits as its factorization.
13164335000602 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6582167500303.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 13164335000602 its reverse (20600053346131), we get a palindrome (33764388346733).
The spelling of 13164335000602 in words is "thirteen trillion, one hundred sixty-four billion, three hundred thirty-five million, six hundred two", and thus it is an aban number.
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