Base | Representation |
---|---|
bin | 111101010011011001… |
… | …1101111110001001100 |
3 | 110120210202012002022111 |
4 | 1322212303233301030 |
5 | 4124103241223430 |
6 | 140251132553404 |
7 | 12340231102654 |
oct | 1724663576114 |
9 | 416722162274 |
10 | 131647601740 |
11 | 50916703766 |
12 | 21620622864 |
13 | c5503361c5 |
14 | 652c231364 |
15 | 3657816c2a |
hex | 1ea6cefc4c |
131647601740 has 24 divisors (see below), whose sum is σ = 276469976160. Its totient is φ = 52657133568.
The previous prime is 131647601711. The next prime is 131647601747. The reversal of 131647601740 is 47106746131.
131647601740 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 131647601693 and 131647601702.
It is not an unprimeable number, because it can be changed into a prime (131647601747) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 534201 + ... + 740719.
It is an arithmetic number, because the mean of its divisors is an integer number (11519582340).
Almost surely, 2131647601740 is an apocalyptic number.
131647601740 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131647601740 is an abundant number, since it is smaller than the sum of its proper divisors (144822374420).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131647601740 is a wasteful number, since it uses less digits than its factorization.
131647601740 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 238401 (or 238399 counting only the distinct ones).
The product of its (nonzero) digits is 84672, while the sum is 40.
The spelling of 131647601740 in words is "one hundred thirty-one billion, six hundred forty-seven million, six hundred one thousand, seven hundred forty".
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