Base | Representation |
---|---|
bin | 1011111110010010101000… |
… | …1010100101110110101111 |
3 | 1201121112121022020200110010 |
4 | 2333210222022211312233 |
5 | 3211142433214304212 |
6 | 43555452322344303 |
7 | 2526060401133534 |
oct | 277445212456657 |
9 | 51545538220403 |
10 | 13164782181807 |
11 | 4216175377923 |
12 | 158750aabb093 |
13 | 7465838cb2c9 |
14 | 337270adad8b |
15 | 17c6a5da203c |
hex | bf92a2a5daf |
13164782181807 has 16 divisors (see below), whose sum is σ = 18585723594240. Its totient is φ = 8260189375872.
The previous prime is 13164782181799. The next prime is 13164782181827. The reversal of 13164782181807 is 70818128746131.
It is not a de Polignac number, because 13164782181807 - 23 = 13164782181799 is a prime.
It is a super-2 number, since 2×131647821818072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13164782181827) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5846544 + ... + 7778922.
It is an arithmetic number, because the mean of its divisors is an integer number (1161607724640).
Almost surely, 213164782181807 is an apocalyptic number.
13164782181807 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
13164782181807 is a deficient number, since it is larger than the sum of its proper divisors (5420941412433).
13164782181807 is a wasteful number, since it uses less digits than its factorization.
13164782181807 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2065982.
The product of its (nonzero) digits is 3612672, while the sum is 57.
The spelling of 13164782181807 in words is "thirteen trillion, one hundred sixty-four billion, seven hundred eighty-two million, one hundred eighty-one thousand, eight hundred seven".
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