Base | Representation |
---|---|
bin | 10011001010001000000… |
… | …001001111111010110111 |
3 | 11122212020002002012110211 |
4 | 103022020001033322313 |
5 | 133032234224140203 |
6 | 2444451104330251 |
7 | 164055065352625 |
oct | 23121001177267 |
9 | 4585202065424 |
10 | 1316542021303 |
11 | 468384715683 |
12 | 1931a3313987 |
13 | 971c3259322 |
14 | 47a144d0515 |
15 | 243a62d4c6d |
hex | 1328804feb7 |
1316542021303 has 2 divisors, whose sum is σ = 1316542021304. Its totient is φ = 1316542021302.
The previous prime is 1316542021297. The next prime is 1316542021357. The reversal of 1316542021303 is 3031202456131.
It is a weak prime.
It is an emirp because it is prime and its reverse (3031202456131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1316542021303 - 217 = 1316541890231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1316542021393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658271010651 + 658271010652.
It is an arithmetic number, because the mean of its divisors is an integer number (658271010652).
Almost surely, 21316542021303 is an apocalyptic number.
1316542021303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316542021303 is an equidigital number, since it uses as much as digits as its factorization.
1316542021303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 1316542021303 its reverse (3031202456131), we get a palindrome (4347744477434).
The spelling of 1316542021303 in words is "one trillion, three hundred sixteen billion, five hundred forty-two million, twenty-one thousand, three hundred three".
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