Base | Representation |
---|---|
bin | 1011111110010101011001… |
… | …1000111010010010100111 |
3 | 1201121121112000100201012002 |
4 | 2333211112120322102213 |
5 | 3211200443134224111 |
6 | 44000054105115515 |
7 | 2526114650460614 |
oct | 277452630722247 |
9 | 51547460321162 |
10 | 13165524133031 |
11 | 421651616a856 |
12 | 1587697488b9b |
13 | 7466715383ba |
14 | 33730147550b |
15 | 17c6eb0ae63b |
hex | bf95663a4a7 |
13165524133031 has 2 divisors, whose sum is σ = 13165524133032. Its totient is φ = 13165524133030.
The previous prime is 13165524133009. The next prime is 13165524133039. The reversal of 13165524133031 is 13033142556131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13165524133031 - 218 = 13165523870887 is a prime.
It is a super-2 number, since 2×131655241330312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13165524133039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6582762066515 + 6582762066516.
It is an arithmetic number, because the mean of its divisors is an integer number (6582762066516).
Almost surely, 213165524133031 is an apocalyptic number.
13165524133031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13165524133031 is an equidigital number, since it uses as much as digits as its factorization.
13165524133031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 97200, while the sum is 38.
Adding to 13165524133031 its reverse (13033142556131), we get a palindrome (26198666689162).
The spelling of 13165524133031 in words is "thirteen trillion, one hundred sixty-five billion, five hundred twenty-four million, one hundred thirty-three thousand, thirty-one".
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