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131664365433631 = 155365384745027
BaseRepresentation
bin11101111011111101111111…
…101110110011001100011111
3122021011222202000012120122101
4131323331333232303030133
5114224142110022334011
61144005435141225531
736506302500364132
oct3573757756631437
9567158660176571
10131664365433631
1138a525a8893668
12129255297022a7
135860b86487b14
14247283701a219
151034d5b78c2c1
hex77bf7fbb331f

131664365433631 has 4 divisors (see below), whose sum is σ = 131664451732312. Its totient is φ = 131664279134952.

The previous prime is 131664365433599. The next prime is 131664365433637. The reversal of 131664365433631 is 136334563466131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131664365433631 - 25 = 131664365433599 is a prime.

It is a super-2 number, since 2×1316643654336312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131664365433637) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40818861 + ... + 43926166.

It is an arithmetic number, because the mean of its divisors is an integer number (32916112933078).

Almost surely, 2131664365433631 is an apocalyptic number.

131664365433631 is a deficient number, since it is larger than the sum of its proper divisors (86298681).

131664365433631 is an equidigital number, since it uses as much as digits as its factorization.

131664365433631 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 86298680.

The product of its digits is 25194240, while the sum is 55.

The spelling of 131664365433631 in words is "one hundred thirty-one trillion, six hundred sixty-four billion, three hundred sixty-five million, four hundred thirty-three thousand, six hundred thirty-one".

Divisors: 1 1553653 84745027 131664365433631