Base | Representation |
---|---|
bin | 11101111100100000101000… |
… | …001101010001111101111010 |
3 | 122021022112201120210101202111 |
4 | 131330200220031101331322 |
5 | 114230244234221002100 |
6 | 1144034505124522534 |
7 | 36512060140622662 |
oct | 3574405015217572 |
9 | 567275646711674 |
10 | 131701551734650 |
11 | 38a67350557a47 |
12 | 1293078725044a |
13 | 5864531624a31 |
14 | 2474563a391a2 |
15 | 1035cd62306ba |
hex | 77c828351f7a |
131701551734650 has 24 divisors (see below), whose sum is σ = 247916270405664. Its totient is φ = 52045914418800.
The previous prime is 131701551734563. The next prime is 131701551734653. The reversal of 131701551734650 is 56437155107131.
It is a junction number, because it is equal to n+sod(n) for n = 131701551734594 and 131701551734603.
It is not an unprimeable number, because it can be changed into a prime (131701551734653) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 15867652686 + ... + 15867660985.
It is an arithmetic number, because the mean of its divisors is an integer number (10329844600236).
Almost surely, 2131701551734650 is an apocalyptic number.
131701551734650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131701551734650 is a deficient number, since it is larger than the sum of its proper divisors (116214718671014).
131701551734650 is a wasteful number, since it uses less digits than its factorization.
131701551734650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31735313766 (or 31735313761 counting only the distinct ones).
The product of its (nonzero) digits is 1323000, while the sum is 49.
The spelling of 131701551734650 in words is "one hundred thirty-one trillion, seven hundred one billion, five hundred fifty-one million, seven hundred thirty-four thousand, six hundred fifty".
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